A portein has been isolated as sodium salt with their molecular formula `Na_(x)P` (this notation means that `xNa^(+)` ions are associated with a negatively charged protein `P^(-x))`. A solution of this salt was prepared by dissolving `0.25g` of this sodium slat of protein in `10g` of water adn ebulliscopic analysis revealed that soluion boils at temperature `5.93 xx 10^(-3).^(@)C` higher than the normal boiling point of pure water. `K_(b)` of water 0`.52 kg mol^(-1)`. Also elemental analysis revealed that the salt contain `1%` sodium metal by weight. Deduce molecular formula and determine molecular weight of acidic form of protein `H_(X)P`.

Answer

`H_(20)P, 45563 amu`

Explanation

`Delta T_(b) = i xx K_(f)xx m`
`5.93xx10^(-3) = ((x+1)xx0.52xx0.25xx1000)/(Mxx10)`
`((x+1))/(M) = 4.56xx10^(-4)` …..(i)
`(M)/(100) = 23 x` ….(ii)
From equation (i) and (ii)
`xx20.34~=20`
Formula of protein `= H_(20)P`
`M = 2300xx20-20xx23+23= 45563` amu