Calculate the boiling point of a solution containing `0.61 g` of benzoic acid in `50 g` of carbon disulphide assuming `84%` dimerization of the acid. The boiling point and `K_(b)` of `CS_(2)` are `46.2^(@)C` and `2.3 kg mol^(-1)`.

Answer

`46.31^(@)C`

Explanation

`i=1 - (alpha)/(2) = 1 - (0.84)/(2) = 0.48`
`DeltaT_(b) = (0.48 xx 2.3 xx 0.61 xx 1000)/(122 xx 50) = 0.1104`
`T_(b) = 46.2 +0.1104 = 46.31^(@)C`