If solution sulphate is considered to be completely dissociated into cations and anions in aqueous solution, the change in freezing point water `(Delta T_(f))`, when `0.01` mole of solution sulphate is dissolved in `1 kg` of water, is: `(K'_(f) = 1.86 kg mol^(-1))`

Options

A. `0.0186 K`
B. `0.0372 K`
C. `0.0558 K`
D. `0.0744 K`

Answer

C

Explanation

`DeltaT_(f) = iK_(f) m`
`= 3 xx 1.86 xx 0.01//1`
`= 0.0558 K`