The degree of dissociation `(alpha)` of a weak electrolyte, `A_(x)B_(y)` is related to van't Hoff's factor `(i)` by the expression:

Options

A. `alpha = (x+y -1)/(i-1)`
B. `alpha = (x+y +1)/(i-1)`
C. `alpha = (i-1)/((x+y-1))`
D. `alpha =(i-1)/(x+y+1)`

Answer

C

Explanation

`{:(AxByrarr,xA^(y+)+,yB^(x-),i=(1-prop+xprop +y prop)),(|,,-,-),(1-prop,xprop,yprop,prop=(i-1)/(x+y-1)):}`