The elevation in boiling point, when `13.44 g` of freshly prepared `CuCI_(2)` are added to one kilogram of water, is [Some useful data, `K_(b) (H_(2)O) = 0.52 kg K mol^(-1), "mol.wt of" CuCI_(2) = 134.4 gm]`

Options

A. `0.05`
B. `0.1`
C. `0.16`
D. `0.21`

Answer

C

Explanation

`DeltaT_(b) = iK_(b) m`
`=3 x 0.52 xx (13.44//134.4)/(1)`
`= 0.156 K`
`=0.16K`