Two coins are tossed simultaneously 500 times with the following frequencies of different outcomes: Two heads: 95 times One tail : 290 times No head: 115 times Find the probability of occurrence of each of these events.

Explanation

Let `E_(1)` = getting two heads = `95`
`E_(2)` = getting one tail = `290`
`E_(3)` = getting no head = `115`
Total number of trials (n) = `500`
`P(E_(1))=(E_(1))/(n)=(95)/(500)=(95)/(500)=19/100=0.19`
`P(E_(2))=(E_(2))/(n)=(290)/(500)=(58)/(100)=0.58`
`P(E_(3))=(E_(3))/(n)=(115)/(500)=(23)/(100)=023`