A tank is filled with a liquid upto a height H, A small hole is made at the bottom of this tank Let `t_(1)` be the time taken to empty first half of the tank and `t_(2)` time taken to empty rest half of the tank then find `(t_(1))/(t_(2))`

Explanation

To solve the problem of finding the ratio \( \frac{t_1}{t_2} \) where \( t_1 \) is the time taken to empty the first half of the tank and \( t_2 \) is the time taken to empty the second half, we can follow these steps:

### Step 1: Understand the problem
We have a tank filled with liquid up to a height \( H \) and a small hole at the bottom. We need to find the time taken to empty the first half of the tank (from height \( H \) to \( \frac{H}{2} \)) and the time taken to empty the second half (from height \( \frac{H}{2} \) to \( 0 \)).

### Step 2: Use Torricelli's Law
According to Torricelli's Law, the time \( t \) taken to empty a tank from a height \( h \) is given by the formula:
\[
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