Home
Class 11
PHYSICS
A cubical block (of sie 2m) of mass 20 k...

A cubical block (of sie 2m) of mass 20 kg slides on inclined plane lubricated with the oil of viscosity `eta=10^(-1)` poise with constant velocity of 10 m/s find out the thickness of layer of liquid (`g=10m//s^(2)`)

Text Solution

Verified by Experts


`F=F'=etaA(dv)/(dz)=mgsintheta(dv)/(dz)=(v)/(h)`
`implies20xx10xxsin30^(@)=etaxx4xx(10)/(h)`
`impliesh=4xx10^(-3)m=4mm`
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY, SURFACE TENSION AND FLUID MECHANICS

    ALLEN|Exercise Exercise 1 (Elasticity)|16 Videos

  • ELASTICITY, SURFACE TENSION AND FLUID MECHANICS

    ALLEN|Exercise Exercise 1 (Surface Tension)|21 Videos

  • CENTRE OF MASS

    ALLEN|Exercise EXERCISE-V B|19 Videos

  • ERROR AND MEASUREMENT

    ALLEN|Exercise Part-2(Exercise-2)(B)|22 Videos

Similar Questions

Explore conceptually related problems

A cubical block (of side 2 m ) of mass 20 kg slides on inclined plane lubricated with the oil of viscosity eta=10^(-1) with constant velocity of 10 ms^(-1) . Find out the thickness of the layer of liquid (take g = 10 ms^(-2) ).

A wooden box of mass 8kg slides down an inclined plane of inclination 30^(@) to the horizontal with a constant acceleration of 0.4ms^(-2) What is the force of friction between the box and inclined plane ? (g = 10m//s^(2)) .

A solid cylinder rolls down an inclined plane of height 3m and reaches the bottom of plane with angular velocity of 2sqrt2 rad//s . The radius of cylinder must be [take g=10m//s^(2) ]

A cylinder of mass 1/sqrt(3)kg is placed on the corner of two inclined planes as shown in the figure.Find the normal reaction in newtons at contact point of cylinder with the slope of inclination 30^(@) g=10m/s^(2)

Block of mass 10 kg is moving on inclined plane with constant velocity 10 m/s. The coedfficient of kinetic friction between incline plane and block is :-

An external force 6N is applied on a sphere of radius R = 10 cm of mass 1 kg and the sphere moves in a liquid with a constant velocity 5 m/s making 530 with the horizontal.The coefficient of viscosity of the liquid is 20//(6pi), in S.I units. (Take g=10 m//s^(2) )

A mass of 1 kg is just able to slide down the slope of an inclined rough surface when the angle of inclination is 60^(@) The minima force necessary to pull the mass up the inclined plane is: (g=10 m//s^(2))

A body of 5 kg weight kept on a rough inclined plane of angle 30^(@) starts sliding with a constant velocity. Then the coefficient of friction is (assume g=10m//s^(2) )

A block of mass 2.0 kg is pushed down an inclined plane of inclination 37^0 with a force of 20N cting parallelto the incline. It is found tht the block moves on the incline with an acceleration of 10 m/s^2 . If the blcok started from rest, find the work done a. by the applied force in the first second b. by the weight of the block in the first second and c. by the frictional force acting on the block in the first second. Take g=10 m/s^2 .