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A drop of water of radius 0.0015 mm is f...

A drop of water of radius 0.0015 mm is falling in air. If the coefficient of viscosity of air is `1.8xx10^(-8)kgm^(-1)s^(-1)` what will be the terminal velocity of the drop. Density of air can be neglected.

Text Solution

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`V_(T)=(2)/(9)(r^(2)(rho-sigma)g)/(eta)=(2xx[(15xx10^(-4))/(1000)]^(2)xx10^(3)xx9.8)/(9xx1.8xx10^(-5))=2.72xx10^(-4)m//s`
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A drop of water of radius 0.0015 mm is falling in air. If the coefficient of viscosity of air is 1.8 xx 10^(-3)kg//m^(3) , what will be the terminal velocity of the drop? Density of water = 1.0 xx 10^(3) kg//m^(2) and g = 9.8 N//kg . Density of air can be neglected.

Knowledge Check

  • A drop of water of radius 0.0015 mm is falling in air .If the cofficient of viscosity of air is 2.0 xx 10^(-5) kg m^(-1)s^(-1) ,the terminal velocity of the drop will be (The density of water = 10^(3) kg m^(-3) and g = 10 m s^(-2) )

    A
    `1.0 xx 10^(-4) m s^(-1)`
    B
    `2.0 xx 10^(-4) m s^(-1)`
    C
    `2.5 xx 10^(-4) m s^(-1)`
    D
    `5.0 xx 10^(-4) m s^(-1)`

  • The terminal velocity of a drop of water of radius 0.0015 mm which is falling in air whose coefficient of viscosity is 2.0xx10^(-5)kgm^(-1)s^(-1) , will be (The density of water =10^(3)kgm^(-3) and g=10ms^(-2) )

    A
    `1.0xx10^(-4)ms^(-1)`
    B
    `2.0xx10^(-4)ms^(-1)`
    C
    `2.5xx10^(-4)ms^(-1)`
    D
    `5.0xx10^(-4)ms^(-1)`

  • An air bubble (radius 0.4 mm) rises up in water. If the coefficient of viscosity of water be 1xx10^(-3)kg//(m-s) , then determine the terminal speed of the bubble density of air is negligible

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    B
    3.048 m/s
    C
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    D
    0.348 m/s

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