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A water drop of radius 1 mm is broken in...

A water drop of radius 1 mm is broken into `10^(6)` identical drops, surface tension of water is 72 dynes/cm find the energy spent in this process.

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To find the energy spent in breaking a water drop of radius 1 mm into \(10^6\) identical drops, we can follow these steps: ### Step 1: Calculate the volume of the original drop The volume \(V\) of a sphere is given by the formula: \[ V = \frac{4}{3} \pi R^3 \] where \(R\) is the radius of the original drop. Given \(R = 1 \text{ mm} = 1 \times 10^{-3} \text{ m}\): ...
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The surface tension of water is 72 dyne//cm. convert it inSI unit.

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Knowledge Check

  • A water drop of radius 1 cm is broken into 1000 equal droplets. If the surface tension of water is 0.075 N/m , then the gain in surface enrgy will be

    A
    0
    B
    `8.5xx10^(-4)` J
    C
    `7.5xx10^(-4)` J
    D
    infinite
  • The work done is breaking a water drop of radius 1 cm into 64 equal droplets (Surface tension of water is 0.07 N/m)

    A
    `1.6 xx 10^(-4)`J
    B
    `264 xx 10^(-4)`J
    C
    `2.64 xx 10^(-4)`J
    D
    `5.28 xx 10^(-4)`J
  • A spherical drop of oil of radius 1 cm is broken into 1000 droplets of equal radii. If the surface tension of oil is 50 dynes / cm , the work done is

    A
    `18pi` ergs
    B
    `180 pi ergs`
    C
    `1800 pi ergs`
    D
    `8000 pi ergs`
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