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The graph shows the extension of a wire of length 1m suspended from the top of a roof at one end and with a load W connected to the other end. If the cross sectional area of the wire is `1mm^(2)`, then the young's modulus of the material of the wire is
(a). `2xx10^(11)Nm^(-2)`
(b). `2xx10^(10)Nm^(-2)`
(c). `(1)/(2)xx10^(11)Nm^(-2)`
(d). none of these

Text Solution

Verified by Experts

The correct Answer is:
B

`Y=(F//A)/(Deltal//l)=(Wl)/(Adeltal)implies(W)/(Deltal)=(YA)/(l)="slope"impliesY=(l)/(A)("slope")=(1)/(10^(-6))((40-20)/((2-1)xx10^(3)))=2xx10^(10)Nm^(-2)`
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Knowledge Check

  • The adjacent graph shows the estension (Deltal) of a wire of length 1m suspended from the top of a roof at one end and with a load W connected to the other end. If the cross-sectional area of the wire is 10^-6m^2 , calculate the Young's modulus of the material of the wire.

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