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There is a soap bubble of radius 2.4xx10...

There is a soap bubble of radius `2.4xx10^(-4)m` in air cylinder which is originally at a pressure of `10^(5)(N)/(m^(2))`. The air in the cylinder is now compressed isothermally until the radius of the bubble is halved. (the surface tension of the soap film is `0.08Nm^(-1))`. The pressure of air in the cylinder is found to be `8.08xx10^(n)(N)/(m^(2))`. What is the value of n?

Text Solution

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The correct Answer is:
`8.08xx10^(5)N//m^(2)`
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