Find the gravitational potential energy of a system of four particles, each of mass `m` placed at the verticles of a square of side `l`. Also obtain the gravitaitonal potential at centre of the square.

Answer

`(-5.41Gm^(2))/(l),(-4sqrt(2)Gm)/(l)`

Explanation

Potential at centre
`=sum(GM)/(r)=(-4GM)/(r)=-(4sqrt(2)GM)/(l)`
Potential eenrgy of the system
`-(4GM^(2))/(l)-(2GM^(2))/(sqrt(2)l)=-(5.41GM^(2))/(l)`