The time period of a satellite of earth is 5 hours. If the separation between the centre of earth and the satellite is increased to 4 times the previous value, the new time period will become-

Options

A. 10 h
B. 80 h
C. 40 h
D. 20 h

Answer

C

Explanation

`becauseTpropR^(3//2)`
`thereforeT_(2)=T_(1)((R_(2))/(R_(1)))^(3//2)=5h(4)^(3//2)=40h`