Waves emitted by two identical sources produces intensity of K unit at a point on screen where path difference between these waves is `lamda`. Calculate the intensity at that point on screen at which path difference is `(lamda)/(4)`

Explanation

To solve the problem, we need to calculate the intensity at a point on the screen where the path difference between the waves from two identical sources is \(\frac{\lambda}{4}\). We know that the intensity at a point where the path difference is \(\lambda\) is \(K\) units.

### Step-by-Step Solution:

1. **Understanding the Given Information**:
- The intensity at a point where the path difference is \(\lambda\) is \(K\).
- The path difference we need to consider now is \(\frac{\lambda}{4}\).

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