In the Young's double slit experiment the central maxima is observed to be `I_(0)`. If one of the slits is covered, then intensity at the central maxima will become-

Options

A. `(I_(0))/(2)`
B. `(I_(0))/(sqrt(2))`
C. `(I_(0))/(4)`
D. `I_(0)`

Answer

C

Explanation

central maxima i.e.,
`I_(0)=(sqrt(I_(1))+sqrt(I_(2)))^(2)impliesI_(0)=(2sqrt(I))^(2)=4`
`therefore=(I_(0))/(4)`
[Intensity due to single slit]