In the Young's double slit experiment using a monochromatic light of wavelength `lamda`, the path difference (in terms of an integer n) corresponding to any point having half the peak

Options

A. `(2n+1)(lamda)/(2)`
B. `(2n+1)(lamda)/(4)`
C. `(2n+1)(lamda)/(8)`
D. `(2n+1)(lamda)/(16)`

Answer

B

Explanation

`I_("net")=I_(0)+I_(0)+2I_(0)cosphi=(I_(max))/(2)=2I_(0)impliescosphi=`
`0impliesphi=npi+(pi)/(2)=(2pi)/(lamda)Deltax impliesDeltax=(2n+1)(lamda)/(4)`