Light wavelength 6000 Å is incident normally on a slit of width `24xx10^(-5)` cm. find out the angular position of seconds minimum from central maximum?

Explanation

To find the angular position of the second minimum from the central maximum in a single-slit diffraction pattern, we can use the formula for the minima in single-slit diffraction.

### Step-by-Step Solution:

1. **Identify the given values:**
- Wavelength of light, \( \lambda = 6000 \, \text{Å} = 6000 \times 10^{-10} \, \text{m} \)
- Width of the slit, \( a = 24 \times 10^{-5} \, \text{cm} = 24 \times 10^{-7} \, \text{m} \)

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