Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Calculate the angular width of central maximum on a screen distance 9 m?

Explanation

To solve the problem of calculating the angular width of the central maximum when light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm, we can follow these steps:

### Step 1: Understand the Problem
We need to find the angular width of the central maximum in a single-slit diffraction pattern. The first minimum on either side of the central maximum defines its width.

### Step 2: Identify Given Values
- Wavelength of light, \( \lambda = 6328 \, \text{Å} = 6328 \times 10^{-10} \, \text{m} \)
- Width of the slit, \( a = 0.2 \, \text{mm} = 0.2 \times 10^{-3} \, \text{m} \)
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