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A 300 mm long tube containing 60 cm^(3) ...

A 300 mm long tube containing 60 `cm^(3)` of sugar solution produces an optical rotations of `10^(@)` when placed in a saccharimeter. If specific rotation of sugar is `60^(@)` calculate the quantity of sugar constained in te tube solution.

Text Solution

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`l=300mm=30cm=3` decimeter, `theta=10^(@),[alpha]_(A)^(T)=60^(@)`, volume of solution `=60cm^(3)`
`theta=[alpha]_(lamda)^(T)lCimpliesC=(theta)/([alpha]_(lamda)^(T)l)=(10^(@))/(60^(@)xx3)=(1)/(18)gcm^(-3)`
Quantity of sugar contained `=(1)/(18)xx60=3.33g`
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Knowledge Check

  • 80 gm of impure sugar when dissolved in a litre of water gives an optical rotation of 9.9^(@) when placed in a tube of length 20 cm. If concentration of sugar solution is 75 gm/litre then specific rotation of sugar is :

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  • If solution of a compound ( 30g//100ml of solution ) has measured rotation of +15^(@) in a 2 dm long sample tube, the specific rotation of this compound is

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    B
    `+7.5^(@)`
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  • If specific rotation of glucose solution is 52^@ and fructose solution -92^@ then what will be specific rotaion of invert sugar ?

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