Home
Class 11
CHEMISTRY
2.5 g of the carbonate of a metal war tr...

2.5 g of the carbonate of a metal war treated with 100 ml of `1 N H_(2)SO_(4)`. After the completion of the reaction, the solution was boiled off to expel `CO_(2)` and was then titrated against 1 N NaOH solution. The volume of alkali that would be consumed, if the equivalent weight of the metal is 20.

Promotional Banner

Similar Questions

Explore conceptually related problems

0.84 g of a metal carbonate reacts exactly with 40 ml of N/2 H_(2)SO_(4) . The equivalent weight of the metal carbonate

100 ml of 2M HCl solution completely neutralises 10 g, of a metal carbonate. Then the equivalent weight of the metal is

100 ml of 2M HCI solution completely neutralises 10 g. of a metal carbonate. Then the equivalent weight of the metal is

If 100 mL of 1 N H_(2)SO_(4) is mixed with 100 mL of 1 M NaOH solution. The resulting solution will be

If 100 mL of 1 N H_(2)SO_(4) is mixed with 100 mL of 1 M NaOH solution. The resulting solution will be

0.84g of metal carbonate reacts exactly with 40 ml of N//2H_2SO_4 . The equivelent weight of the metal carbonate is

100 ml of 0.1 N NaOH is mixed with 50 ml of 0.1 N H_2SO_4 . The pH of the resulting solution is