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A solution is 0.01 M Kl and 0.1 M KCl. I...

A solution is 0.01 M Kl and 0.1 M KCl. If solid `AgNO_(3)` is added to the solution, what is the `[l^(-)]` when AgCl begins to precipitate?
`[K_(SP)(Agl)=1.5xx10^(-16),K_(SP)(AgCl)=1.8xx10^(-10)]`

A

`3.5xx10^(-7)`

B

`6.1xx10^(-8)`

C

`2.2xx10^(-7)`

D

`8.3xx10^(-8)`

Text Solution

Verified by Experts

The correct Answer is:
D
When AgCl start precipitating concentration of `[Ag^(+)]` in the solution
`[Ag^(+)]=(K_(spAgCl))/([Cl^(-)])=(1.8xx10^(-10)xx10)/(0.1)`
`[Ag^(+)]=1.8xx10^(-9)`
`K_(spAgl)=[Ag^(+)][I^(-)]`
`1.5xx10^(-16)=1.8xx10^(-9)[I^(-)]`
`[I^(-)]=(1.5xx10^(-16))/(1.8xx10^(-9))=0.833xx10^(-7)`
`=8.3xx10^(-8)`
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