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200 mL of 0.4M solution of CH(3)COONa is...

200 mL of 0.4M solution of `CH_(3)COONa` is mixed with 400 mL of 0.2 M solution of `CH_(3)COOH`. After complete mixing, 400 mL of 0.1 M NaCl is added to it. What is the pH of the resulting solution? `[K_(a)` of `CH_(3)COOH=10^(-5)]`

A

5.4

B

6

C

5

D

6.2

Text Solution

Verified by Experts

The correct Answer is:
C
`pH=p_(Ka)+log(([CH_(3)COONa])/([CH_(3)COOH]))=5+log((200xx0.4)/(400xx0.2))=5`
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