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how much work in kJ mol^(-1) unit is don...

how much work in kJ `mol^(-1)` unit is done by reversible and isothermal expansion of 1.2 mole of an ideal gas to 10 times of its original volume at `27^(@)C`?

A

`4.191`

B

`6.892`

C

`-6.892`

D

`-4.191`

Text Solution

Verified by Experts

The correct Answer is:
C
`W=-2.303nRTlog((V_(2))/(V_(1)))=-2.303xx1.2xx8.314xx10^(-3)xx300log((10V_(1))/(V_(1)))=-6.892kJmol^(-1)`
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