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AgNO(3) solution will not give white pre...

`AgNO_(3)` solution will not give white precipitate with

A

`[Co(NH_(3))_(3)Cl_(3)]`

B

`[Co(NH_(3))_(4)Cl_(2)]Cl`

C

`[Co(NH_(3))_(5)Cl]Cl_(2)`

D

`[Co(NH_(3))_(6)]Cl_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A

no free `Cl^(-)` in the ionisation sphere.
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An isomerr of the complex CoBrCl_(2)(en)_(2)(H_(2)O) , on reaction with concentrated H_(2)SO_(4) (dehydrating agent), suffers no loss in weight and on reaction with AgNO_(3) solution it gives only white precipitate, which is soluble in NH_(3) solution. Q. The incorrect statement about complex is:

An isomerr of the complex CoBrCl_(2)(en)_(2)(H_(2)O) , on reaction with concentrated H_(2)SO_(4) (dehydrating agent), suffers no loss in weight and on reaction with AgNO_(3) solution it gives only white precipitate, which is soluble in NH_(3) solution. Q. The correct formula of the complex is:

In coordination chemistry there are a veriety of methods applied to find out the structure of complexes. One method involves treating the complex with known reagents and from the nature of reaction, the formula0 of the complex can be predicted. An isomers of the complex Co(en)_(2)(H_(2)O)Cl_(2)Br , on reaction with concentrated H_(2)SO_(4) (dehydrating agent ) it suffers loss in weight and on reaction with AgNO_(3) solution it gives a white precipitate which is soluble in NH_(3)(aq) . The correct formula of the complex is :

In coordination chemistry there are a variety of methods applied to find out the structure of complexes.One method involves treating the complex with known reagents and from the nature of reaction, the formula of the complex can be predicted.An isomer of the complex Co(en)_2(H_2O)Cl_2Br ,on reaction with concentrated H_2SO_4 (dehydrating agent) it suffers loss in weight and on reaction with AgNO_3 solution it gives a white precipitate which is soluble in NH_3 (aq). If one mole of original complex is treated with excess Pb(NO_3)_2 solution, then the number of moles of white precipitate (of PbCl_2 ) formed will be :

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