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1.0 mole of Fe reacts completely with 0....

1.0 mole of Fe reacts completely with 0.65 mole of `O_(2)` to give a mixture of only FeO and `Fe_(2)O_(3)` the mole ratio of ferrous oxide to ferric oxide is

A

`2:2`

B

`4:3`

C

`1:2`

D

`2:7`

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The correct Answer is:
To find the mole ratio of ferrous oxide (FeO) to ferric oxide (Fe2O3) when 1 mole of iron reacts with 0.65 moles of oxygen, we can follow these steps: ### Step 1: Write the chemical reactions 1. **For FeO formation**: \[ 2Fe + O_2 \rightarrow 2FeO \] This indicates that 2 moles of iron react with 1 mole of oxygen to produce 2 moles of FeO. 2. **For Fe2O3 formation**: \[ 4Fe + 3O_2 \rightarrow 2Fe_2O_3 \] This indicates that 4 moles of iron react with 3 moles of oxygen to produce 2 moles of Fe2O3. ### Step 2: Define variables for moles of products Let: - \( A \) = moles of FeO produced - \( B \) = moles of Fe2O3 produced ### Step 3: Set up the equations based on the total moles of iron and oxygen 1. From the total moles of iron: \[ A + B = 1 \quad \text{(since we have 1 mole of Fe)} \] 2. From the total moles of oxygen: - For FeO: \( \frac{A}{2} \) moles of \( O_2 \) are needed. - For Fe2O3: \( \frac{3B}{4} \) moles of \( O_2 \) are needed. \[ \frac{A}{2} + \frac{3B}{4} = 0.65 \quad \text{(since we have 0.65 moles of O2)} \] ### Step 4: Solve the equations 1. Substitute \( B \) from the first equation into the second: \[ B = 1 - A \] Substitute into the oxygen equation: \[ \frac{A}{2} + \frac{3(1 - A)}{4} = 0.65 \] Simplifying: \[ \frac{A}{2} + \frac{3}{4} - \frac{3A}{4} = 0.65 \] Combine like terms: \[ \frac{2A}{4} - \frac{3A}{4} = 0.65 - 0.75 \] \[ -\frac{A}{4} = -0.10 \] Multiply both sides by -4: \[ A = 0.4 \] 2. Now find \( B \): \[ B = 1 - A = 1 - 0.4 = 0.6 \] ### Step 5: Calculate the moles of FeO and Fe2O3 - Moles of FeO = \( A = 0.4 \) - Moles of Fe2O3 = \( \frac{B}{2} = \frac{0.6}{2} = 0.3 \) ### Step 6: Find the mole ratio The mole ratio of FeO to Fe2O3 is: \[ \text{Mole Ratio} = \frac{0.4}{0.3} = \frac{4}{3} \] ### Final Answer The mole ratio of ferrous oxide to ferric oxide is \( 4:3 \). ---

To find the mole ratio of ferrous oxide (FeO) to ferric oxide (Fe2O3) when 1 mole of iron reacts with 0.65 moles of oxygen, we can follow these steps: ### Step 1: Write the chemical reactions 1. **For FeO formation**: \[ 2Fe + O_2 \rightarrow 2FeO \] This indicates that 2 moles of iron react with 1 mole of oxygen to produce 2 moles of FeO. ...
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