Home
Class 12
CHEMISTRY
Iodate ions can be reduced to iodine by ...

Iodate ions can be reduced to iodine by iodide ions as per the given redox reaction in acidic medium.
`lO_(3)^(-)(aq)+l^(-)(aq)tol_(2)(S)`.
How many moles of iodine are produced for every mole of iodate ions consumed in the reaction?

A

1

B

2.5

C

3

D

5

Text Solution

Verified by Experts

The correct Answer is:
C

`IO_(3)^(-)+5I^(-)+6H^(-)to3I_(2)(s)+3H_(2)O`
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY AND BALANCING REDOX REACTION

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|5 Videos
  • THERMODYNAMICS AND THERMOCHEMISTRY

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|5 Videos

Similar Questions

Explore conceptually related problems

Iodate ions (IO_(3)^(-)) can be reduced to iodine by iodide ions. The half equation which represent the redox reaction are: IO_(3)^(-)(aq.)+6H^(+)(aq.)+5e to (1)/(2)I_(2)(s)+3H_(2)O(l) . . . (i) I^(-)(aq.) to (1)/(2)I_(2)(s)+e^(-) . . . (ii) How many moles of iodine are produced for every mole of iodate ions consumed int he reaction?

1 mole of Fe^(2+) ions are oxidised to Fe^(3+) ions with the help of ( in acidic medium)

1 " mol of " IO_(3)^(ɵ) ions is heated with excess of I^(ɵ) ions in the presence of acidic conditions as per the following equation IO_(3)^(ɵ)+I^(ɵ)toI_(2) How many moles of acidified bypo solution will be required to react completely with I_(2) thus produced?

In acidic medium Zn reduces nitrate ion ot NH_(4)^(+) ion according to the reaction underset("(unbalanced)")(Zn+NO_(3)^(-))rarrZn^(2+)+NH_(4)^(+)+H_(2)O How many moles of HCl are required to reduce half a mole of NaNO_(3) completely? Assume the availability of sufficient Zn.