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if mp and m(alpha) are masses of proton ...

if `m_p` and `m_(alpha)` are masses of proton and `alpha-`particles find ratio of momentum of a proton and an `alpha-`particle which are accelerated fromr est by a potential difference of 200 V.

A

`(m_(p))/(2m_(alpha))`

B

`(2m_(alpha))/(m_(p))`

C

`(sqrt((m_(p))/(2m_(alpha))))`

D

`sqrt((2m_(p))/(m_(alpha)))`

Text Solution

Verified by Experts

The correct Answer is:
C
`QV=(1)/(2)mv^(2)`
`thereforev=sqrt((2QV)/(m))`
`thereforev_(P)=sqrt((2QV)/(m_(P)))` or `V_(alpha)=sqrt((2xx2QV)/(m_(alpha)))`
`m_(P).V_(P)=sqrt(2QV.m_(P))` & `m_(alpha).v_(alpha)=sqrt(4QV.m_(alpha))`
`therefore` ratio `=sqrt((m_(P))/(2m_(alpha)))`
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