An aqueous solution of a metal ion (A) on reaction with Kl gives a black brownish ppt (B) and this aqueous suspension on treatment with excess Kl gives orange yellowish solution. Then A is

Options

A. `pb^(2+)`
B. `Bl^(3+)`
C. `Hg_(2)^(2+)`
D. `Hg^(2+)`

Answer

B

Explanation

`underset((A))(Bi^(3+))overset(KI)tounderset("black ppt")underset((B))(BiI_(3))underset(KI)overset("excess")tounderset("yellow brown solution")([BiI_(4)]^(-))`