A beam of ions with velocity ` 2xx 10^(5) ` m/s enters normally into a uniform magnetic field of ` 4 xx 10^(-2)` T. if the specific charge to the ions is ` 5xx 10^(7) ` C/kg, the radius of the circular path described will be

A beam of ions with velocity 2xx10^5ms^-1 enters normally into a uniform magnetic field of 0*04 tesla. If the specific charge of ion is 5xx10^7Ckg^-1 , find the radius of the circular path described.

Electrons move at right angles to a magnetic field of 1.5xx10^(-2) Tesla with a speed of 6xx10^(7)m//s . If the specific charge of the electron is 1.7xx10^(11)C//kg . The radius of the circular path will be

A beam of protons moving with a velocity of 4 xx 10^(5) m/s enters a uniform magnetic field of 0.3 T at an angle of 60◦ with the magnetic field. What is the radius of the helical path described by the proton beam? [m_p=1.67 xx 10^(-27) kg and the charge on the proton =1.6 xx 10^(-19) C]

A proton beam enters magnetic field of 10^(-4) "Wb//m^(2) normally. If the specific charge of the proton is 10^(11) C//kg and its velocity is 10^(9)m//s then the radius of the circle described will be

A proton beam enters magnetic field of 10^(-4) "Wb//m^(2) normally. If the specific charge of the proton is 10^(11) C//kg and its velocity is 10^(9)m//s then the radius of the circle described will be

A proton beam enters a magnetic field of 10^(-4)Wb m^(-2) normally. If the specific charge of the proton is 10^11 C kg^(-1) and its velocity is 10^9 ms^-1 ,then the radius of the circle described will be: