The less stable oxidation state of `Cr` are:

Options

A. `Cr^(2+)`
B. `Cr^(3+)`
C. `Cr^(4+)`
D. `Cr^(6+)`

Answer

ACD

Explanation

`Cr^(3+)` is most stable because in aqueous solution it has higher `CFSE` on account of half filled `t_(2g)^(3)` energy level of `3d` orbitals in octahedral spliting.