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The spin-only magnetic moment [in units ...

The spin-only magnetic moment [in units of Bohr magneton, `(mu_(B)` of `Ni^(2+)` in aqueous solution would be (atomic number of `Ni=28)`

A

`2.84`

B

`4.90`

C

`0`

D

`1.73`

Text Solution

Verified by Experts

The correct Answer is:
1

Valence shell electron configuration of `._28Ni^(2+)` is `3d^(8) 4s^(0)`, or

So, number of unpaired electron(n)=2
therefore `mu=sqrtn(n+2)=sqrt2(2+2)=sqrt8approx2.84`
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