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A particle is moving along a circle of r...

A particle is moving along a circle of radius `R` with a uniform speed `v`. At `t = 0` , the particle is moving along the east. Find the average acceleration (magnitude and direction) in (a) `1//4 th` revolution and (b) `1//2` revolution.

A

`(V^(2))/(sqrt(2)piR)S-W`

B

`(2sqrt(2)v^(2))/(piR)S-W`

C

`(2sqrt(2)v^(2))/(piR)S-E`

D

`0`

Text Solution

Verified by Experts

The correct Answer is:
B

A paerticle is ………..

change in velocity `Delta vecv = vecv_(t) - vecv_(i)`
`Delta vecv= sqrt(2)v - s-w`

time taken `t =(piR//2)/(V) = (piR)/(2V)`
`a_(avg) = (Delta vecv)/(t) = (sqrt(2)v)/((pi R//2v))S-W`
`= (2sqrt(2)v^(2))/(pi R) S - W`
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