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A man moves with a velocity vecv(1) duri...

A man moves with a velocity `vecv_(1)` during time interval `t_(1)`. Then he moves with velocity `vecv_(2)` (which is perpendicular to the `vecv_(1)`) during time interval `t_(2)`. The incorrect statement is :

A

`|Delta vecv| = sqrt(v_(1)^(2)+v_(2)^(2))`

B

`s= |vecv_(1)t_(1)+vecv_(2)t_(2)|` = displacement

C

`D = |vecv_(1)|t_(1)+|vecv_(2)|t_(2)` = distance

D

`vecv_(av) = (vecv_(1)+vecv_(2))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
A man ………………
`vecV_(av) = (vecV_(1)t_(1)+vecV_(2)t_(2))/(t_(1)+t_(2))`
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