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A particle starts its motion from rest u...

A particle starts its motion from rest under the action of a constant force. If the distance covered in first `10 s` is `s_1` and the covered in the first `20 s` is `s_2`, then.

A

`s_(2)=2s_(1)`

B

`s_(2)=3s_(1)`

C

`s_(2)=4s_(1)`

D

`s_(2)=s_(1)`

Text Solution

Verified by Experts

The correct Answer is:
C
A particle ………..
If the particle is moving in a straight line under the action of a constant force then distance covered
`s=ut+(1)/(2)at^(2)`
Since the body starts from rest `u = 0`
`:. s = (1)/(2)at^(2)`
Now, `s_(1)= (1)/(2)a(10)^(2)` ............(i)
and, `s_(2)= (1)/(2)a(20)^(2)` .............. (ii)
Deividing Eq (i) and Eq (ii) we get
`(s_(1))/(s_(2)) = ((10)^(2))/((20)^(2))`
`implies s_(2) = 4s_(1)`
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