Home
Class 12
PHYSICS
A particle is moving on a straight line ...

A particle is moving on a straight line with velocity (v) as a function of time (t) according to relation `v = (5t^(2) - 3t + 2)m//s` . Now give the answer of following questions :
Acceleration of particle at the end of `3^(rd)` second of motion is :

A

`27 m//sec^(2)`

B

`16 m//sec^(2)`

C

`39 m//sec^(2)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
Acceleration of …………..
`a = (dV)/(dt) = 10t - 3`
`a at t = 3 "second is a" = 10xx3 - 3 = 27 m//s^(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle is moving on a straight line with velocity (v) as a function of time (t) according to relation v = (5t^(2) - 3t + 2)m//s . Now give the answer of following questions : Velocity of particle at t = 3 sec. is :

A particle is moving on a straight line with velocity (v) as a function of time (t) according to relation v = (5t^(2) - 3t + 2)m//s . Now give the answer of following questions : Velocity of particle when acceleration is zero is :

A particle moving in a straight line has its velocit varying with time according to relation v = t^(2) - 6t +8 (m//s) where t is in seconds. The CORRECT statement(s) about motion of this particle is/are:-

A particle is moving in a straight line according as s=45t+11t^2-t^3 then the time when it come to rest is

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Which of the following graph may be correct for the motion of particle

A particle moves along a straight line its velocity dipends on time as v=4t-t^(2) . Then for first 5 s :

A particle is moving in a striaght line according as S=15t+6t^2-t^3 , then the time it will come to rest is

A particle is moving in a straight line. The variation of position ‘x’ as a function of time ‘t’ is given as x = (t^3 – 6t^2 20t 15) m. The velocity of the body when its acceleration becomes zero is :

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Distance travelled by particle in 0 to 3 second time interval is :

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Time interval in which particle speed continuous decreases?