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A body which was released from rest, sli...

A body which was released from rest, slides down on an inclined plane of inclination `theta`. The coefficient of friction dowh the plane varies as `mu = kx` where k is a spositive constant and x is the distance moved by the body down the plane. The speed of the body 'v' versus distance 'x' graph will be as :

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
C
A body which ………..
`a = g (sin theta - kx cos theta)`
`theta = constt`.
`v = g(sin theta x - (kx^(2))/(2)cos theta)`

Hence required graph will be as
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