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A block of mass 10kg is placed on rough ...

A block of mass 10kg is placed on rough inclined plasne of variable angle `theta` and friction coefficient `mu_(s)=mu_(k)=3//4`. When `theta` is `37^(@)` net reaction force applied by inclined is `vecN_(1)` and when `theta = 53^(@)` net reaction force applied by inclined is `vecN_(2)` , then `|vecN_(1)|-|vecN_(2)|` is :

A

`0`

B

`25N`

C

`-25N`

D

`-37N`

Text Solution

Verified by Experts

The correct Answer is:
B
A block of …………..
`Mg - sqrt(1+mu^(2))Mg cos theta`
`= 25 N`.
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