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A slab of 40 kg lying on a frictionales ...

A slab of `40 kg` lying on a frictionales floor and a block of 10 kg rests on the slab as shown in the figure. The coefficients of static and kinetic friction between the slab and the block are `0.6` and `0.4` respectively. If a force of `100 N` is applied on the block, then the acceleration the slab will be `(g = 10 m//s^(2))`

A

`15.5m//s^(2)`

B

`155m//s^(2)`

C

`1.5m//s^(2)`

D

`1m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
A slab of ………..
Let both the block and slab are moving together

`100 - f = 10a`
`f = 40a`
`100 = 50a`
`a = 2`
`f = 40xx2=80`
`f_(lim)=muxx10xxg`
`= 0.6xx10xx10`
`= 60 N`
so block and slab will not move together

`40 = 40a`
`a = 1 m//s^(2)`
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