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A particle starts circular motion with r...

A particle starts circular motion with radius `R` about a fixed point with unifrom angular acceleration `2 rad//sec^(2)` If the time at which net force on particle makes an angle `45^(@)` with direction of its velocity is `(1)/(sqrt(n))sec`. Then value of n is :

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The correct Answer is:
2
A particle ……………

`tan45^(@)= (a_(c ))/(a_(t))` , `alpha = 2= (d omega)/(dt)`
`int d omega = int 2dt` , `omega = 2t`
`omega^(2)R = alpha R`
`4t^(2)=2`
`t = (1)/(sqrt(2)) sec` .
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