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Find the distance travelled by a body ha...

Find the distance travelled by a body having velocity `v = 1 - t^(2)` from t = 0 tol t = 2 sec .

A

`3m`

B

`2m`

C

`1m`

D

`4m`

Text Solution

Verified by Experts

The correct Answer is:
B

Find the …………….

distance `= int_(0)^(2)|1-t^(2)|dt`
distance `= int_(0)^(1)(1-t^(2))dt+int^(2)-(1-t^(2))dt`
distance `= [t - (t^(3))/(3)]_(0)^(1) - [t-(t^(3))/(3)]_(1)^(2) = (2)/(3)- ((-4)/(3)) = 2m`
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Knowledge Check

  • The position of a body moving along x-axis at time t is given by x= (t^(2)-4t+6)m . The distance travelled by body in time interval t = 0 to t = 3 s is

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  • A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the distance travelled (in meters) by the particle from time t = 0 to t = 1 s will be :

    A
    `2/pi`
    B
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  • If the distance s travelled by a body in time t is given by s = a/t + bt^2 then the acceleration equals

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    B
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