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A force of (3hati-1.5hatj)N acts on 5kg ...

A force of `(3hati-1.5hatj)N` acts on `5kg` body. The body is at a position of `(2hati-3hatj)m` and is travelling at `4m//s`. The force acts on the body until it is at the position `(hati+5hatj)m`. Calculate final.speed.

A

`sqrt(20)m//s`

B

`sqrt(10)m//s`

C

`sqrt(40)m//s`

D

`sqrt(50)m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
A force of …………
`5 kg`
`vecF = 3hati-1.5hatj`
`veca=(3)/(5)hati-(3)/(10)hatj`
`vecs=(hati+5hatj)-(2hati-3hatj)=(-hati+8hatj)m`
`w = vecF.vecs= (1)/(2)m(v^(2)-u^(2))`
`v = sqrt(10)m//s`
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