Home
Class 12
PHYSICS
The time dependence of a physical quanti...

The time dependence of a physical quantity `P` is given by `P = P_(0)e^(-alpha t^(2))` , where `alpha` is a constant and `t` is time . Then constant `alpha` is//has

A

`[T^(-1)]`

B

`[T^(-2)]`

C

`[T^(1)]`

D

`[T^(2)]`

Text Solution

Verified by Experts

The correct Answer is:
B

`P = P_(0)e^(-alpha t^(2))` ………….
`[alpha t^(2)]=[M^(@)L^(@)T^(@)]`
`implies [alpha] = [T^(2)]`
Promotional Banner

Similar Questions

Explore conceptually related problems

The time dependence of a physical quantity P is given by P=P_(0) exp (-alpha t^(2)) , where alpha is a constant and t is time. The constant alpha

The time dependence of a physical quantity P is given by P= P_0 exp (-alpha t^(2)) , where alpha is a constant and t is time. The constant alpha

Time dependence of a physical quantity P is given by P =P_0 exp(-alpha t^2), where alpha is a constant and t is time. The constant alpha is

The time dependance of a physical quantity 'P' is given by P=P_(0)exp(-at^(2)) , where a is a constant and 't' is time . The constant a is

A physical quantity Q is given by Q=Q_(0)e^(-alphat^(2)) where t is the time and alpha is a constant. What is the dimensional formula for alpha ?

The time dependence of a physical quantity P is given by P=P_0 exp(prop t^2) , where prop is constant prop is represented as [M^0 L^x T^(-2)] . Find x

The position of a particle at time t, is given by the equation, x(t) = (v_(0))/(alpha)(1-e^(-alpha t)) , where v_(0) is a constant and alpha gt 0 . The dimensions of v_(0) & alpha are respectively.

The function f is given by f = A sin alpha x + B cos beta t , where x is displacement and t is the time. The dimensions of alpha//beta is