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Force acting on a pasrticle is vecF = (a...

Force acting on a pasrticle is `vecF = (alpha y hati +beta xy hatj)`. Find the work done by this force, when pasrticle is moved alolng the line `2x = 3y` from origin to the point `(3,2)` {take quantities in `SI` units and `alpha = 1, beta = 1`}

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The correct Answer is:
7
Force acting ………..
`W = int vecF.dvecr`
`= int(ydx + xydy)`
`:' 2x = 3y`
`= int_(0)^(2)((3)/(2)ydy+(3)/(2)y^(2)dy)`
`:. Dx= (3)/(2)dy`
`= [(3)/(4)y^(2)+(y^(3))/(2)]_(0)^(2) = 7` Joule.
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