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A block of weight W is dragged across th...

A block of weight `W` is dragged across the horizontal floor from `A` to `B` by the constant vertical force `P` acting at the end of the rope. Calculate the work done on the block by the force `P = (sqrt(3)+1)N`. Assume that block does not lift off the floor. `(g = 10m//s^(2))`

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The correct Answer is:
4
A block of ………….
`W = Px`
`= P[(h)/(sin30^(@))-(h)/(sin60^(@))]`
`= 2Ph[1-(1)/(sqrt(3))]= (2[sqrt(3)-1])/(sqrt(3))Ph`
`= (2(sqrt(3)-1)(sqrt(3)+1)(sqrt(3)))/(sqrt(3)) = 4J`
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