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A person in an elevator accelerating upw...

A person in an elevator accelerating upwards with an acceleration of `4 ms^(-2)` tosses a coin vertically. Upwards with a speed of `21 ms^(-1)` with respect to himself. The time at which coin will back into his hand is `(g = 10 ms^(-2))`

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The correct Answer is:
3
A person ……………
`t = (2v)/(g+a) = ((2xx21))/((10+4)) = (42)/(14) = 3 sec` .
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