Home
Class 12
PHYSICS
A uniform disc of mass m & radius R is p...

A uniform disc of mass `m` & radius `R` is pivoted at its centre `O` with its plane vertical as shown in figure A circular portion of disc of radius `(R )/(2)` is removed from it. The time period of small oscillations of remaining portion about `O` is -

A

`3pi sqrt((R )/(g))`

B

`pi sqrt((13R)/(g))`

C

`2pi sqrt((39R)/(16g))`

D

`2pisqrt((7R)/(6g))`

Text Solution

Verified by Experts

The correct Answer is:
B

A uniform …………
`T = 2pi sqrt((I)/(mgy_(cm)))`
`I = (MR^(2))/(2) - ((1)/(2)(M)/(4)((R )/(2))^(2) + (M)/(4)((R )/(2))^(2))= (13MR^(2))/(32)`
`y_(cm) = (R )/(6)`
`T = 2pi sqrt((13)/(4) (R )/(g))`
Promotional Banner

Similar Questions

Explore conceptually related problems

A uniform disc of mass m & radius R is pivoted at its centre O with its plane vertical as shown in figure A circular portion of disc of radius (R)/(2) is removed from it. Then choose the correct option(s)

A uniform disc of mass M and radius R is hinged at its centre C. A force F is applied on the disc as shown. At this instant, the angular acceleration of the disc is

A uniform disc of mass M and radius R is hinged at its centre C . A force F is applied on the disc as shown . At this instant , angular acceleration of the disc is

A disc of radius R is pivoted at its rim. The period for small oscillations about an axis perpendicular to the plane of disc is

From a circular disc of radius R , another disc of diameter R is removed. Locate c.m. of the remaining portion.

A disc of mass m and radius R moves in the x-y plane as shown in Fig. The angular momentum of the disc about the origin O at the instant shown is

A disc of radius a/2 is cut out from a uniform disc of radius a as shown in figure . Find the X Coordinate of centre of mass of remaining portion

From a circular disc of radius R, a square is cut out with a radius as its diagonal. The center of mass of remaining portion is at a distance from the center)