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In a resonance tube experiment, resonanc...

In a resonance tube experiment, resonance occures first at `32.0 cm` and then at `100.0cm`. What is the percentage error in the measurement of end correction.

A

`2.5%`

B

`5%`

C

`7.5%`

D

`10%`

Text Solution

Verified by Experts

The correct Answer is:
D
In a resonance ………….
`e = (l_(3)+3l_(1))/(2) = 2.0cm`
`de = (dl_(2)+3dl_(1))/(2)`
`% "error" = (dl_(2)+3dl_(1))/(2xxe)xx100`
`= (0.1+3xx0.1)/(2xx2.0)xx100=10%`
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