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In a termperature scale X ice point of w...

In a termperature scale `X` ice point of water is assigned a value of `20^(@) X` and the boiling point of water is assiggned a value of `220^(@) X`. In another scale `Y` the ice poiny of water is assigned a value of `-20^(@) Y` and the boiling point is given a value of `380^(@)Y`. Then temperature on both the scales will be same is

A

`30^(@)`

B

`40^(@)`

C

`50^(@)`

D

`60^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
Change of `1^(@)X =` change of `2^(@)Y`
At a perticlular temperature, if we are `x` divisions way from `20^(@)X` and `y` divisionws away from `-20^(@)Y` then-
`20 + x = -20 + 2x rArr x = 40`
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