A specimen of silicon is to be made p-type semiconductor. For this one atom of indium, on an average is doped in `5xx10^(7)` silicon atoms. If the number density of silicon is `5xx10^(28) "atoms"//m^(3)`, then the number of acceptor atoms per `cm^(3)` is

Explanation

The doping of one indium atoms in silicon semiconductor will rpoduce on eaceeptor atom in p-type semiconductor. Since one indium atom has been dopped per `5xx10^(7)` silicon atoms so number density of acceptor atoms in silicon `=(5xx10^(28))/(5xx10^(7))=10^(21) "atom"//m^(3)=10^(15) "atoms"//cm^(3)`